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Diffstat (limited to '2024/13/day13a.cpp')
| -rw-r--r-- | 2024/13/day13a.cpp | 62 |
1 files changed, 62 insertions, 0 deletions
diff --git a/2024/13/day13a.cpp b/2024/13/day13a.cpp new file mode 100644 index 0000000..9dccff9 --- /dev/null +++ b/2024/13/day13a.cpp | |||
| @@ -0,0 +1,62 @@ | |||
| 1 | /* | ||
| 2 | This is the dumb solution I wrote before actually thinking how to solve | ||
| 3 | the problem. Check out day13b.cpp for a better solution (just remove the | ||
| 4 | +N in the input-reading part). | ||
| 5 | |||
| 6 | Also, both this file and day13b.cpp take a different input format than | ||
| 7 | what was given. I used clean.sh to convert from 'input-original' to 'input'. | ||
| 8 | */ | ||
| 9 | |||
| 10 | #include <algorithm> | ||
| 11 | #include <iostream> | ||
| 12 | #include <map> | ||
| 13 | #include <ranges> | ||
| 14 | #include <set> | ||
| 15 | #include <sstream> | ||
| 16 | #include <string> | ||
| 17 | #include <string_view> | ||
| 18 | #include <vector> | ||
| 19 | using namespace std; | ||
| 20 | |||
| 21 | #define INF 999999 | ||
| 22 | |||
| 23 | class Machine { | ||
| 24 | public: | ||
| 25 | pair<int, int> a, b, prize; | ||
| 26 | |||
| 27 | Machine(int a1, int a2, int b1, int b2, int p1, int p2) : | ||
| 28 | a(a1, a2), b(b1, b2), prize(p1, p2) {} | ||
| 29 | }; | ||
| 30 | |||
| 31 | int main() { | ||
| 32 | string line; | ||
| 33 | int a1, a2, b1, b2, p1, p2; | ||
| 34 | vector <Machine> machines; | ||
| 35 | while (cin >> a1 >> a2) { | ||
| 36 | cin >> b1 >> b2; | ||
| 37 | cin >> p1 >> p2; | ||
| 38 | getline(cin, line); | ||
| 39 | machines.push_back(Machine(a1, a2, b1, b2, p1, p2)); | ||
| 40 | } | ||
| 41 | |||
| 42 | int tot = 0; | ||
| 43 | for (auto m : machines) { | ||
| 44 | int minp = INF; | ||
| 45 | for (int i = 0; i <= 100; i++) { | ||
| 46 | int x = m.prize.first-m.a.first*i; | ||
| 47 | int y = m.prize.second-m.a.second*i; | ||
| 48 | if (x % m.b.first != 0 || y % m.b.second != 0) | ||
| 49 | continue; | ||
| 50 | int a = x / m.b.first; | ||
| 51 | int b = y / m.b.second; | ||
| 52 | if (a != b) | ||
| 53 | continue; | ||
| 54 | minp = min(minp, 3*i+a); | ||
| 55 | } | ||
| 56 | tot += minp == INF ? 0 : minp; | ||
| 57 | } | ||
| 58 | |||
| 59 | cout << tot << endl; | ||
| 60 | |||
| 61 | return 0; | ||
| 62 | } | ||
